450x^2+1800x-600=0

Solution for 450x^2+1800x-600=0 equation:

450x^2+1800x-600=0

a = 450; b = 1800; c = -600;
Δ = b2-4ac
Δ = 18002-4·450·(-600)
Δ = 4320000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4320000}=\sqrt{1440000*3}=\sqrt{1440000}*\sqrt{3}=1200\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1800)-1200\sqrt{3}}{2*450}=\frac{-1800-1200\sqrt{3}}{900}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1800)+1200\sqrt{3}}{2*450}=\frac{-1800+1200\sqrt{3}}{900}
$